Example zero
Suppose I consists of a single element. Then a zero stable module is pair of maps and
such that
is surjective,
is injective and
.
The existence of zero-stable modules is only possible then if the dimension of W is at least twice the dimension of V. In the case of the smallest possible example of this (when W is 2-dimensionl) we are essentially picking two non-zero orthogonal vectors in W.
Example 1
Let be a directed graph and V be chosen so that
for all h. Then zero-stable modules are possible only when
for all
, and will correspond to a choice of zero-stable module of the type in example zero for each non-trivial
.
As a more specific example consider the directed graph consisting of four vertices and four edges formed into a circle. Let and
and
. Then you can think of a zero-stable module as a pair of bases (each an orthogonal basis) for
.
May 4, 2009 at 2:55 pm |
Note: I calculate
in that last example to be
. With sufficient choice of
the defining
-action will have four fixed points in the closure, none in the interior.