Zero-stability: Examples

By trdunlap2

Example zero

Suppose I consists of a single element. Then a zero stable module is pair of maps a:W\rightarrow V and b:V\rightarrow W such that a is surjective, b is injective and ab=0.

The existence of zero-stable modules is only possible then if the dimension of W is at least twice the dimension of V. In the case of the smallest possible example of this (when W is 2-dimensionl) we are essentially picking two non-zero orthogonal vectors in W.

Example 1

Let (I,\Omega) be a directed graph and V be chosen so that Hom(V_{s(h)},V_{e(h)})=0 for all h. Then zero-stable modules are possible only when \dim W_i \ge 2 \dim V_i for all i\in I, and will correspond to a choice of zero-stable module of the type in example zero for each non-trivial V_i.

As a more specific example consider the directed graph consisting of four vertices and four edges formed into a circle. Let V_1=V_3=\mathbb{C} and V_2=V_0=0 and W_i=\mathbb{C}^2. Then you can think of a zero-stable module as a pair of bases (each an orthogonal basis) for \mathbb{C}^2.

One Response to “Zero-stability: Examples”

  1. trdunlap2 Says:

    Note: I calculate \mathfrak{z}^s_0 in that last example to be (\mathbb{C}^*)\times  (\mathbb{C}^*). With sufficient choice of \rho the defining \mathbb{C}^*-action will have four fixed points in the closure, none in the interior.

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