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	<title>Tom's Math Weblog</title>
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		<title>A remark on a problem from my undergrad</title>
		<link>http://trdunlap2.wordpress.com/2009/11/06/a-remark-on-a-problem-from-my-undergrad/</link>
		<comments>http://trdunlap2.wordpress.com/2009/11/06/a-remark-on-a-problem-from-my-undergrad/#comments</comments>
		<pubDate>Sat, 07 Nov 2009 01:01:36 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
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		<guid isPermaLink="false">http://trdunlap2.wordpress.com/?p=396</guid>
		<description><![CDATA[Sometime, I think early, in my years at University of Michigan.  I discovered somehow the following phenomenon.
Begin with any positive integer  then define for  let  where .  If ever  then   In fact, it would seem that, no matter which number you start with this will always happen.
For example [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=396&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Sometime, I think early, in my years at University of Michigan.  I discovered somehow the following phenomenon.</p>
<p>Begin with any positive integer <img src='http://l.wordpress.com/latex.php?latex=a_1%3Da_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1=a_2' title='a_1=a_2' class='latex' /> then define for <img src='http://l.wordpress.com/latex.php?latex=n%5Cge+2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n\ge 2' title='n\ge 2' class='latex' /> let <img src='http://l.wordpress.com/latex.php?latex=a_%7Bn%2B1%7D%3Da_n%2Bc_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_{n+1}=a_n+c_n' title='a_{n+1}=a_n+c_n' class='latex' /> where <img src='http://l.wordpress.com/latex.php?latex=a_n%3Db_n%5Ctimes+n%2Bc_n%2C+0%5Cle+c_n++%3Cn&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_n=b_n\times n+c_n, 0\le c_n  &lt;n' title='a_n=b_n\times n+c_n, 0\le c_n  &lt;n' class='latex' />.  If ever <img src='http://l.wordpress.com/latex.php?latex=b_n%3Dc_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_n=c_n' title='b_n=c_n' class='latex' /> then <img src='http://l.wordpress.com/latex.php?latex=b_N%3Dc_N%3Db_n%2C+%5Cforall+n%3EN&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_N=c_N=b_n, \forall n&gt;N' title='b_N=c_N=b_n, \forall n&gt;N' class='latex' />  In fact, it would seem that, no matter which number you start with this will always happen.</p>
<p>For example if you begin with <img src='http://l.wordpress.com/latex.php?latex=a_1%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1=1' title='a_1=1' class='latex' /> it takes 397 steps to stabalize at <img src='http://l.wordpress.com/latex.php?latex=a_397%3D97%5Ctimes+397+%2B+97&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_397=97\times 397 + 97' title='a_397=97\times 397 + 97' class='latex' />. On the other hand if you begin with <img src='http://l.wordpress.com/latex.php?latex=a_1%3D3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1=3' title='a_1=3' class='latex' /> then <img src='http://l.wordpress.com/latex.php?latex=a_2%3D1%5Ctimes+2%2B1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_2=1\times 2+1' title='a_2=1\times 2+1' class='latex' /> so <img src='http://l.wordpress.com/latex.php?latex=a_3%3D1%5Ctimes+3+%2B+1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_3=1\times 3 + 1' title='a_3=1\times 3 + 1' class='latex' /> etc.  In otherwords, sometimes it may happen soon, sometimes it may take rather a long time.</p>
<p>Only recently I realized that the possibility that this always stabilizes should not be very surprising. Suppose that prior to stability the value <img src='http://l.wordpress.com/latex.php?latex=%5Cfrac%7Bc_n%7D%7Bn%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\frac{c_n}{n}' title='\frac{c_n}{n}' class='latex' /> behaved randomly.  If <img src='http://l.wordpress.com/latex.php?latex=b_n%3Cn&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_n&lt;n' title='b_n&lt;n' class='latex' /> then there would be a <img src='http://l.wordpress.com/latex.php?latex=%5Cfrac1n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\frac1n' title='\frac1n' class='latex' /> chance that <img src='http://l.wordpress.com/latex.php?latex=c_n%3Db_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='c_n=b_n' title='c_n=b_n' class='latex' />.  Since <img src='http://l.wordpress.com/latex.php?latex=a_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_n' title='a_n' class='latex' /> grows by no more than n, at some point we must have <img src='http://l.wordpress.com/latex.php?latex=a_N%3CN%5E2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_N&lt;N^2' title='a_N&lt;N^2' class='latex' /> and so <img src='http://l.wordpress.com/latex.php?latex=b_n%3Cn%2C+%5Cforall+n%3EN&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_n&lt;n, \forall n&gt;N' title='b_n&lt;n, \forall n&gt;N' class='latex' />.  At that point, if we haven&#8217;t already stabilized the probability that we eventually stabilize is <img src='http://l.wordpress.com/latex.php?latex=%5Csum_%7Bn%3DN%7D%5E%5Cinfty+%5Cfrac1n%5Cprod_%7Bm%3DN%7D%5E%7Bn-1%7D%5Cfrac%7Bm-1%7D%7Bm%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\sum_{n=N}^\infty \frac1n\prod_{m=N}^{n-1}\frac{m-1}{m}' title='\sum_{n=N}^\infty \frac1n\prod_{m=N}^{n-1}\frac{m-1}{m}' class='latex' />.  Noting that the partial sums of this series are <img src='http://l.wordpress.com/latex.php?latex=%5Cfrac+%7BM%7D%7BN%2BM-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\frac {M}{N+M-1}' title='\frac {M}{N+M-1}' class='latex' /> we deduce that the limit is equal to 1.  In otherwords the probability of <strong>never </strong>stabilizing is zero.</p>
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		<item>
		<title>Second Calculation level=rank=2</title>
		<link>http://trdunlap2.wordpress.com/2009/08/08/second-calculation-levelrank2/</link>
		<comments>http://trdunlap2.wordpress.com/2009/08/08/second-calculation-levelrank2/#comments</comments>
		<pubDate>Sun, 09 Aug 2009 02:12:36 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://trdunlap2.wordpress.com/?p=371</guid>
		<description><![CDATA[This time we will try to find the quiver variety components corresponding to the four figures:

Found in the level two  representation weight diagram:

If my level-rank duality calculations are correct (very similar to those from last post) the dimension vectors will be .
As before we have  and  by the &#8220;limit&#8221; condition. Thus we [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=371&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>This time we will try to find the quiver variety components corresponding to the four figures:<br />
<img src="http://trdunlap2.files.wordpress.com/2009/08/4lsl2basiselements.png?w=247&#038;h=228" alt="4Lsl2basiselements" title="4Lsl2basiselements" width="247" height="228" class="alignnone size-full wp-image-373" /><br />
Found in the level two <img src='http://l.wordpress.com/latex.php?latex=%5Cmathfrak%7Bsl%7D_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathfrak{sl}_2' title='\mathfrak{sl}_2' class='latex' /> representation weight diagram:<br />
<img src="http://trdunlap2.files.wordpress.com/2009/08/lsl2example.png?w=133&#038;h=85" alt="Lsl2example" title="Lsl2example" width="133" height="85" class="alignnone size-full wp-image-374" /></p>
<p>If my level-rank duality calculations are correct (very similar to those from last post) the dimension vectors will be <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbf%7Bw%7D%3D%281%2C1%29%2C%5Cmathbf%7Bv%7D%3D%282%2C2%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbf{w}=(1,1),\mathbf{v}=(2,2)' title='\mathbf{w}=(1,1),\mathbf{v}=(2,2)' class='latex' />.</p>
<p>As before we have <img src='http://l.wordpress.com/latex.php?latex=a_1%5Cneq+0+%5Cneq+b_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1\neq 0 \neq b_2' title='a_1\neq 0 \neq b_2' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=a_2%3D0%3Db_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_2=0=b_1' title='a_2=0=b_1' class='latex' /> by the &#8220;limit&#8221; condition. Thus we can again deduce that <img src='http://l.wordpress.com/latex.php?latex=x%5Coverline+x%3D%5Coverline+y+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x\overline x=\overline y y' title='x\overline x=\overline y y' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=%5Coverline+x+x%3Dy%5Coverline+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline x x=y\overline y' title='\overline x x=y\overline y' class='latex' /> by the <img src='http://l.wordpress.com/latex.php?latex=%5Cmu%5E%7B-1%7D%280%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu^{-1}(0)' title='\mu^{-1}(0)' class='latex' /> condition.  The limit condition additionally tells us that each of these compositions, and the composition <img src='http://l.wordpress.com/latex.php?latex=%5Coverline+x%5Ccdot+%5Coverline+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline x\cdot \overline y' title='\overline x\cdot \overline y' class='latex' />, must be nilpotent.  This might be sufficient to satisfy the limit condition &#8212; technically we should require that any loop involving at least one bar must be nilpotent.</p>
<p>So the only thing left to answer is the &#8220;stability&#8221; condition.  I&#8217;m still working on this but I believe there are two basic ways the stability could be satisfied:(1) there is a path beginning with <img src='http://l.wordpress.com/latex.php?latex=a_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1' title='a_1' class='latex' /> and ending at <img src='http://l.wordpress.com/latex.php?latex=b_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_2' title='b_2' class='latex' /> such that the partial paths give a basis for the whole space (see below for an example) or (2) there are two paths from <img src='http://l.wordpress.com/latex.php?latex=a_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1' title='a_1' class='latex' /> to <img src='http://l.wordpress.com/latex.php?latex=b_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_2' title='b_2' class='latex' /> who together span the whole space.</p>
<p>Example: one way to satisfy the stability condition is if <img src='http://l.wordpress.com/latex.php?latex=a_1%281%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1(1)' title='a_1(1)' class='latex' />,<img src='http://l.wordpress.com/latex.php?latex=xa_1%281%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='xa_1(1)' title='xa_1(1)' class='latex' />,<img src='http://l.wordpress.com/latex.php?latex=yxa_1%281%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='yxa_1(1)' title='yxa_1(1)' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=xyxa_1%281%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='xyxa_1(1)' title='xyxa_1(1)' class='latex' /> form a basis for V and if <img src='http://l.wordpress.com/latex.php?latex=b_2xyxa_1%281%29%5Cneq+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_2xyxa_1(1)\neq 0' title='b_2xyxa_1(1)\neq 0' class='latex' />.  In that case I have used the sage notebook (sagenb.org) to apply the composition and nilpotency conditions to get four subcases:</p>
<p>Subcase 1:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+1%5C%5C1+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; 1\\1 &amp; 0\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; 1\\1 &amp; 0\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D%5Coverline+y_%7B11%7D+%26+0%5C%5C-%5Coverline+y_%7B11%7Dy_%7B21%7D+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; 0\\-\overline y_{11}y_{21} &amp; 0\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; 0\\-\overline y_{11}y_{21} &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5Cy_%7B21%7D+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}0 &amp; 0\\y_{21} &amp; 1\end{matrix}\right)' title='y=\left(\begin{matrix}0 &amp; 0\\y_{21} &amp; 1\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>Subcase 2:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+1%5C%5C1+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; 1\\1 &amp; 0\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; 1\\1 &amp; 0\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D%5Coverline+y_%7B11%7D+%26+%5Coverline+y_%7B12%7D%5C%5C+%5Coverline+y_%7B12%7D+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; \overline y_{12}\\ \overline y_{12} &amp; 0\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; \overline y_{12}\\ \overline y_{12} &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 1\end{matrix}\right)' title='y=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 1\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+%5Coverline+y_%7B12%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; \overline y_{12}\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; \overline y_{12}\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>Subcase 3:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+1%5C%5C+1+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D%5Coverline+y_%7B11%7D+%26+%5Cfrac%7B1%7D%7B2%7D%5Coverline+y_%7B11%7Dy_%7B21%7D%5C%5C+-%5Cfrac%7B1%7D%7B2%7D%5Coverline+y_%7B11%7Dy_%7B21%7D+%26+-%5Cfrac%7B1%7D%7B4%7D%5Coverline+y_%7B11%7Dy_%7B21%7D%5E%7B2%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; \frac{1}{2}\overline y_{11}y_{21}\\ -\frac{1}{2}\overline y_{11}y_{21} &amp; -\frac{1}{4}\overline y_{11}y_{21}^{2}\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; \frac{1}{2}\overline y_{11}y_{21}\\ -\frac{1}{2}\overline y_{11}y_{21} &amp; -\frac{1}{4}\overline y_{11}y_{21}^{2}\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7D-%5Cfrac%7B1%7D%7B4%7Dy_%7B21%7D%5E%7B2%7D+%26+0%5C%5C+y_%7B21%7D+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}-\frac{1}{4}y_{21}^{2} &amp; 0\\ y_{21} &amp; 1\end{matrix}\right)' title='y=\left(\begin{matrix}-\frac{1}{4}y_{21}^{2} &amp; 0\\ y_{21} &amp; 1\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D-%5Cfrac%7B1%7D%7B8%7Dy_%7B21%7D%5E%7B3%7D%5Coverline+y_%7B11%7D+%26+-%5Cfrac%7B1%7D%7B4%7D%5Coverline+y_%7B11%7Dy_%7B21%7D%5E%7B2%7D%5C%5C+%5Cfrac%7B1%7D%7B4%7D%5Coverline+y_%7B11%7Dy_%7B21%7D%5E%7B2%7D+%26+%5Cfrac%7B1%7D%7B2%7D%5Coverline+y_%7B11%7Dy_%7B21%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}-\frac{1}{8}y_{21}^{3}\overline y_{11} &amp; -\frac{1}{4}\overline y_{11}y_{21}^{2}\\ \frac{1}{4}\overline y_{11}y_{21}^{2} &amp; \frac{1}{2}\overline y_{11}y_{21}\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}-\frac{1}{8}y_{21}^{3}\overline y_{11} &amp; -\frac{1}{4}\overline y_{11}y_{21}^{2}\\ \frac{1}{4}\overline y_{11}y_{21}^{2} &amp; \frac{1}{2}\overline y_{11}y_{21}\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>Subcase 4:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+1%5C%5C+1+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7Dy_%7B11%7D+%26+0%5C%5C+y_%7B21%7D+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}y_{11} &amp; 0\\ y_{21} &amp; 1\end{matrix}\right)' title='y=\left(\begin{matrix}y_{11} &amp; 0\\ y_{21} &amp; 1\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>Where the basis for writing the matrices is chosen to be the basis mentioned above.</p>
<p>On the other hand if we consider modules for which the path <img src='http://l.wordpress.com/latex.php?latex=x%5Coverline+x+x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x\overline x x' title='x\overline x x' class='latex' /> generates a basis we only get two subcases:</p>
<p>Subcase 1:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+1%5C%5C+1+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D%5Coverline+y_%7B11%7D%5Cneq0+%26+0%5C%5C+0+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}\overline y_{11}\neq0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}\overline y_{11}\neq0 &amp; 0\\ 0 &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+%5Cfrac+1+%7B%5Coverline+y_%7B11%7D%7D%5C%5C+%5Cfrac+1+%7B%5Coverline+y_%7B11%7D%7D+%26+y_%7B22%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}0 &amp; \frac 1 {\overline y_{11}}\\ \frac 1 {\overline y_{11}} &amp; y_{22}\end{matrix}\right)' title='y=\left(\begin{matrix}0 &amp; \frac 1 {\overline y_{11}}\\ \frac 1 {\overline y_{11}} &amp; y_{22}\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 1\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 1\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>Subcase 2:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+1%5C%5C+1+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; 1\\ 1 &amp; 0\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D%5Coverline+y_%7B11%7D+%26+%5Coverline+y_%7B12%7D%5Cneq0%5C%5C+%5Coverline+y_%7B12%7D+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; \overline y_{12}\neq0\\ \overline y_{12} &amp; 0\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}\overline y_{11} &amp; \overline y_{12}\neq0\\ \overline y_{12} &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+%5Cfrac+1+%7B%5Coverline+y_%7B12%7D%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; \frac 1 {\overline y_{12}}\end{matrix}\right)' title='y=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; \frac 1 {\overline y_{12}}\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+0%5C%5C+0+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 1\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}0 &amp; 0\\ 0 &amp; 1\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>(Notice that this subcase and subcase 2 above intersect when <img src='http://l.wordpress.com/latex.php?latex=%5Coverline+y_12%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline y_12=1' title='\overline y_12=1' class='latex' />.)</p>
<p>But for the path <img src='http://l.wordpress.com/latex.php?latex=%5Coverline+yyx&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline yyx' title='\overline yyx' class='latex' /> there will be only one case:</p>
<table>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+-%5Cfrac%7By_%7B11%7D%7D%7B%5Coverline%7Bx%7D_%7B12%7D%5E%7B2%7D%7D%5C%5C+1+%26+%5Cfrac%7By_%7B11%7D%7D%7B%5Coverline%7Bx%7D_%7B12%7D%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=\left(\begin{matrix}0 &amp; -\frac{y_{11}}{\overline{x}_{12}^{2}}\\ 1 &amp; \frac{y_{11}}{\overline{x}_{12}}\end{matrix}\right)' title='x=\left(\begin{matrix}0 &amp; -\frac{y_{11}}{\overline{x}_{12}^{2}}\\ 1 &amp; \frac{y_{11}}{\overline{x}_{12}}\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7By%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D%5Cfrac%7B%5Coverline%7Bx%7D_%7B12%7D%7D%7By_%7B11%7D%7D+%26+1%5C%5C+0+%26+0%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{y}=\left(\begin{matrix}\frac{\overline{x}_{12}}{y_{11}} &amp; 1\\ 0 &amp; 0\end{matrix}\right)' title='\overline{y}=\left(\begin{matrix}\frac{\overline{x}_{12}}{y_{11}} &amp; 1\\ 0 &amp; 0\end{matrix}\right)' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=y%3D%5Cleft%28%5Cbegin%7Bmatrix%7Dy_%7B11%7D%5Cneq0+%26+0%5C%5C+-%5Coverline%7Bx%7D_%7B12%7D+%26+1%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y=\left(\begin{matrix}y_{11}\neq0 &amp; 0\\ -\overline{x}_{12} &amp; 1\end{matrix}\right)' title='y=\left(\begin{matrix}y_{11}\neq0 &amp; 0\\ -\overline{x}_{12} &amp; 1\end{matrix}\right)' class='latex' />,</td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Coverline%7Bx%7D%3D%5Cleft%28%5Cbegin%7Bmatrix%7D0+%26+%5Coverline%7Bx%7D_%7B12%7D%5Cneq0%5C%5C+0+%26+-%5Cfrac%7B%5Coverline%7Bx%7D_%7B12%7D%5E%7B2%7D%7D%7By_%7B11%7D%7D%5Cend%7Bmatrix%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline{x}=\left(\begin{matrix}0 &amp; \overline{x}_{12}\neq0\\ 0 &amp; -\frac{\overline{x}_{12}^{2}}{y_{11}}\end{matrix}\right)' title='\overline{x}=\left(\begin{matrix}0 &amp; \overline{x}_{12}\neq0\\ 0 &amp; -\frac{\overline{x}_{12}^{2}}{y_{11}}\end{matrix}\right)' class='latex' /></td>
</tr>
</table>
<p>I was on going to do all possible paths &#8212; but I begin to realize this isn&#8217;t a good way to approach things.  For starters I don&#8217;t have a good idea when these subcases lie on the same component of the quiver variety.</p>
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		<title>Calculation when level=rank=2</title>
		<link>http://trdunlap2.wordpress.com/2009/07/27/calculation-when-levelrank2/</link>
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		<pubDate>Tue, 28 Jul 2009 02:14:51 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
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		<description><![CDATA[I will use the formula on the top of page 35 from Nakajima&#8217;s &#8220;Quiver Varieties and Branching&#8221;:
; .
Where the first &#8220;t&#8221; in the second equation indicates transposing (according to the process described on page 33) the generalized young diagram  and the second &#8220;t&#8221; is given by the formula (on page 34):
.
 are suitable choices [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=350&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>I will use the formula on the top of page 35 from Nakajima&#8217;s &#8220;Quiver Varieties and Branching&#8221;:<br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cmathbf%7Bw%7D%3D%5Csum+w_i%5CLambda_i+%3D+%5Csum+%5CLambda_%7B%5Cmu_p%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbf{w}=\sum w_i\Lambda_i = \sum \Lambda_{\mu_p}' title='\mathbf{w}=\sum w_i\Lambda_i = \sum \Lambda_{\mu_p}' class='latex' />; <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbf%7Bw%7D-%5Cmathbf%7Bv%7D%3D%5Csum+w_i%5CLambda_i+-+v_i%5Calpha_i+%3D%5Coverline%7B%5Csp%7Bt%7D%5Clambda%7D%2Bt%5Cdelta%5EY&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbf{w}-\mathbf{v}=\sum w_i\Lambda_i - v_i\alpha_i =\overline{\sp{t}\lambda}+t\delta^Y' title='\mathbf{w}-\mathbf{v}=\sum w_i\Lambda_i - v_i\alpha_i =\overline{\sp{t}\lambda}+t\delta^Y' class='latex' />.<br />
Where the first &#8220;t&#8221; in the second equation indicates transposing (according to the process described on page 33) the generalized young diagram <img src='http://l.wordpress.com/latex.php?latex=%5Clambda&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\lambda' title='\lambda' class='latex' /> and the second &#8220;t&#8221; is given by the formula (on page 34):<br />
<img src='http://l.wordpress.com/latex.php?latex=t%3D%5Clangle+d%5EX%2C%5Cbar%5Cmu%5Crangle-%5Clangle+d%2CM%28%5Cmu%29%5Crangle&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='t=\langle d^X,\bar\mu\rangle-\langle d,M(\mu)\rangle' title='t=\langle d^X,\bar\mu\rangle-\langle d,M(\mu)\rangle' class='latex' />.<br />
<img src='http://l.wordpress.com/latex.php?latex=d%5EY%2C+%5Cdelta%5EY%2C+d%5EX%2C+%5Cdelta%5EX&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='d^Y, \delta^Y, d^X, \delta^X' title='d^Y, \delta^Y, d^X, \delta^X' class='latex' /> are suitable choices for &#8220;d&#8221; and &#8220;<img src='http://l.wordpress.com/latex.php?latex=%5Cdelta&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\delta' title='\delta' class='latex' />&#8221; in affine <img src='http://l.wordpress.com/latex.php?latex=%5Ctilde%7BL%5Cmathfrak%7Bsl%7D_2%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\tilde{L\mathfrak{sl}_2}' title='\tilde{L\mathfrak{sl}_2}' class='latex' /> (which in this case is on &#8220;both sides&#8221; of the level-rank duality).<br />
And <img src='http://l.wordpress.com/latex.php?latex=%5Clangle+d%2C+M%28%5Cmu%29%5Crangle&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\langle d, M(\mu)\rangle' title='\langle d, M(\mu)\rangle' class='latex' /> is (I believe) the coefficient of M in the formula for d(M) found near the bottom of page 32.</p>
<p>My goal is to find the cycles corresponding to the first two triangles in my list of polytopes so I use:<br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cmu%3D%5Cdelta%5EX%2B%5CLambda_0%2B%5CLambda_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu=\delta^X+\Lambda_0+\Lambda_1' title='\mu=\delta^X+\Lambda_0+\Lambda_1' class='latex' /><br />
<img src='http://l.wordpress.com/latex.php?latex=%5Coverline%5Clambda%3D%5Coverline%7B%5Csp%7Bt%7D%5Clambda%7D%3D%5CLambda_0%2B%5CLambda_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\overline\lambda=\overline{\sp{t}\lambda}=\Lambda_0+\Lambda_1' title='\overline\lambda=\overline{\sp{t}\lambda}=\Lambda_0+\Lambda_1' class='latex' /><br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cmu_1%3D0%2C+%5Cmu_1%3D-1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu_1=0, \mu_1=-1' title='\mu_1=0, \mu_1=-1' class='latex' /><br />
Some of the notation is very confusing, I understand.  I&#8217;m sorry, I don&#8217;t know what to do with it: at the end of the day the dimension vectors we are concerned about are <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbf%7Bw%7D%3D%281%2C1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbf{w}=(1,1)' title='\mathbf{w}=(1,1)' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbf%7Bv%7D%3D%281%2C1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbf{v}=(1,1)' title='\mathbf{v}=(1,1)' class='latex' /></p>
<table>
<tbody>
<tr>
<td rowspan="4"><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cleftarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\leftarrow' title='\leftarrow' class='latex' /></td>
<td rowspan="4"><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Crightarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\rightarrow' title='\rightarrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Crightarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\rightarrow' title='\rightarrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cleftarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\leftarrow' title='\leftarrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cdownarrow%5Cuparrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\downarrow\uparrow' title='\downarrow\uparrow' class='latex' /></td>
<td></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cdownarrow%5Cuparrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\downarrow\uparrow' title='\downarrow\uparrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
<td></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
</tr>
</tbody>
</table>
<p>We want to replace the arrows in this diagram with maps (in order of appearance top to bottom left to right) <img src='http://l.wordpress.com/latex.php?latex=y%2C%5Cbar+y%2Cx%2C%5Cbar+x%2Cb_1%2Ca_1%2Cb_2%2Ca_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y,\bar y,x,\bar x,b_1,a_1,b_2,a_2' title='y,\bar y,x,\bar x,b_1,a_1,b_2,a_2' class='latex' /> in such a way that it satisfies three conditions which I abbreviate as the &#8220;<img src='http://l.wordpress.com/latex.php?latex=%5Cmu%5E%7B-1%7D%280%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu^{-1}(0)' title='\mu^{-1}(0)' class='latex' />&#8221; (this is not the same <img src='http://l.wordpress.com/latex.php?latex=%5Cmu&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu' title='\mu' class='latex' />&#8230; sorry), &#8220;stability&#8221; and &#8220;limit&#8221; conditions.</p>
<p>The &#8220;<img src='http://l.wordpress.com/latex.php?latex=%5Cmu%5E%7B-1%7D%280%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu^{-1}(0)' title='\mu^{-1}(0)' class='latex' />&#8221; condition in our case (for and for other choices of <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbf+w+%5Cmathbf+v&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbf w \mathbf v' title='\mathbf w \mathbf v' class='latex' /> but still r=l=2) implies:<br />
<img src='http://l.wordpress.com/latex.php?latex=a_1b_1%2B%5Cbar+x+x%3Dy%5Cbar+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1b_1+\bar x x=y\bar y' title='a_1b_1+\bar x x=y\bar y' class='latex' /><br />
<img src='http://l.wordpress.com/latex.php?latex=a_2b_2%2B%5Cbar+y+y%3Dx%5Cbar+x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_2b_2+\bar y y=x\bar x' title='a_2b_2+\bar y y=x\bar x' class='latex' /></p>
<p>The &#8220;Stability&#8221; condition has two halves. First that every vector v in the top half has &#8220;Origins&#8221; i.e. <img src='http://l.wordpress.com/latex.php?latex=v%3D%5Csum+f_k%28%5Ceta_k%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='v=\sum f_k(\eta_k)' title='v=\sum f_k(\eta_k)' class='latex' /> where  <img src='http://l.wordpress.com/latex.php?latex=%5Ceta_k&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\eta_k' title='\eta_k' class='latex' /> live in the bottom half and <img src='http://l.wordpress.com/latex.php?latex=f_k&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f_k' title='f_k' class='latex' /> are chosen from appropriate paths in the quiver. And second that every non-zero v in the top half has &#8220;Futures&#8221; i.e. <img src='http://l.wordpress.com/latex.php?latex=g%28v%29%5Cneq+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g(v)\neq 0' title='g(v)\neq 0' class='latex' /> for some path g terminating in the bottom half.</p>
<p>The &#8220;Limit&#8221; condition requires that the action of t (not the same as either previous t&#8230; sorry) given on page 30 can be &#8220;controled&#8221; as <img src='http://l.wordpress.com/latex.php?latex=t%5Crightarrow%5Cinfty&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='t\rightarrow\infty' title='t\rightarrow\infty' class='latex' /> by action of <img src='http://l.wordpress.com/latex.php?latex=G_V&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_V' title='G_V' class='latex' /> described on page 5 (just before eq. 2.1 )</p>
<p>Something to notice right away because it will be useful in future calculations: taking the two halves of &#8220;Stability&#8221; together gives paths <img src='http://l.wordpress.com/latex.php?latex=g%5Ccirc+f%3AW%5Ej%5Crightarrow+W&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g\circ f:W^j\rightarrow W' title='g\circ f:W^j\rightarrow W' class='latex' /> on which <img src='http://l.wordpress.com/latex.php?latex=G_V&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_V' title='G_V' class='latex' /> has no control! The &#8220;Limit&#8221; condition requires that the image of such a composition must lie in <img src='http://l.wordpress.com/latex.php?latex=W%5E%7B%3Cj%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='W^{&lt;j}' title='W^{&lt;j}' class='latex' />. (Superscript refers to the decomposition into 1-dimensional subspaces given by <img src='http://l.wordpress.com/latex.php?latex=%5Cmu&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu' title='\mu' class='latex' /> &#8212; use of the <img src='http://l.wordpress.com/latex.php?latex=%5Cle&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\le' title='\le' class='latex' /> is short hand for the corresponding filtration.)</p>
<p>In our case we have <img src='http://l.wordpress.com/latex.php?latex=b_2%3D0%2Ca_1%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_2=0,a_1=0' title='b_2=0,a_1=0' class='latex' />. For example if the image of <img src='http://l.wordpress.com/latex.php?latex=a_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1' title='a_1' class='latex' /> is non-zero the &quot;Futures&quot; condition says it must escape but, according to the &quot;Limit&quot; condition, in doing so it can only afford to accumulate <img src='http://l.wordpress.com/latex.php?latex=m_1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='m_1' title='m_1' class='latex' /> orders of t and every possible exiting accumulates at least <img src='http://l.wordpress.com/latex.php?latex=m_1%2B1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='m_1+1' title='m_1+1' class='latex' />. The argument for <img src='http://l.wordpress.com/latex.php?latex=b_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_2' title='b_2' class='latex' /> is quite similar replacing &quot;image&quot; with &quot;kernel&quot;, &quot;Futures&quot; with &quot;Origins&quot; etc..</p>
<p>Furthermore we get:<br />
<img src='http://l.wordpress.com/latex.php?latex=a_1%5Cneq0%5Cneq+b_2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1\neq0\neq b_2' title='a_1\neq0\neq b_2' class='latex' />,<br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cbar+y%3D0%5CRightarrow+x%5Cneq+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\bar y=0\Rightarrow x\neq 0' title='\bar y=0\Rightarrow x\neq 0' class='latex' /> and<br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cbar+y%5Cneq+0%5CRightarrow+y%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\bar y\neq 0\Rightarrow y=0' title='\bar y\neq 0\Rightarrow y=0' class='latex' />.<br />
(Moding out by the <img src='http://l.wordpress.com/latex.php?latex=G_V&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='G_V' title='G_V' class='latex' /> action in this case we can assume <img src='http://l.wordpress.com/latex.php?latex=a_1%3D1%3Db_2%3A%5Cmathbb%7BC%7D%5Crightarrow%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_1=1=b_2:\mathbb{C}\rightarrow\mathbb{C}' title='a_1=1=b_2:\mathbb{C}\rightarrow\mathbb{C}' class='latex' /></p>
<p>The two components, then, correspond to diagrams:</p>
<table>
<tbody>
<tr>
<td rowspan="2"><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cbar+y%5Crightarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\bar y\rightarrow' title='\bar y\rightarrow' class='latex' /></td>
<td rowspan="2"><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%5Cdashrightarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x\dashrightarrow' title='x\dashrightarrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cdownarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\downarrow' title='\downarrow' class='latex' /></td>
<td></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cuparrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\uparrow' title='\uparrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
<td></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
</tr>
</tbody>
</table>
<p>and </p>
<table>
<tbody>
<tr>
<td rowspan="2"><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cdashleftarrow+y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\dashleftarrow y' title='\dashleftarrow y' class='latex' /></td>
<td rowspan="2"><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=x%5Crightarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x\rightarrow' title='x\rightarrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cdownarrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\downarrow' title='\downarrow' class='latex' /></td>
<td></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cuparrow&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\uparrow' title='\uparrow' class='latex' /></td>
</tr>
<tr>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
<td></td>
<td><img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}' title='\mathbb{C}' class='latex' /></td>
</tr>
</tbody>
</table>
<p>Where the solid line indicates the map is non-zero and dashed line indicates the map may be zero.</p>
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		<title>GRTEALA 1: Review of the situation</title>
		<link>http://trdunlap2.wordpress.com/2009/07/08/grteala-1-review-of-the-situation/</link>
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		<pubDate>Wed, 08 Jul 2009 18:42:37 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
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		<description><![CDATA[Update: Notes and video from the summer school is available here.
I should have been posting while I was at the conference.  But anyway I&#8217;ll try to post as much as I can remember, before I forget it.
Geometric Satake gives a correspondence from representation theory to subvarieties of an affine Grassmanian.  MV-cycles help give [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=347&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Update: Notes and video from the summer school is available <a href="http://www.mathstat.uottawa.ca/~asavag2/grteala.html">here</a>.</p>
<p>I should have been posting while I was at the conference.  But anyway I&#8217;ll try to post as much as I can remember, before I forget it.</p>
<p>Geometric Satake gives a correspondence from representation theory to subvarieties of an affine Grassmanian.  MV-cycles help give a better handle on them but are still rather abstract.  MV-polytopes , introduced by Jared Anderson, are more &#8220;hands on&#8221; in terms of being able to do direct computations.  But you need to know what they are first, and their original definition as moment map images of MV-cycles doesn&#8217;t really help.  At least if you know they are a convex hill of the torus fixed-points appear in the *closure* of an MV-cycle then you&#8217;re done &#8212; but this still requires more-or-less calculating the MV-cycles and taking their closure.</p>
<p>Kamnitzer&#8217;s thesis provided a few ways to get direct handle on MV-polytopes avoiding MV-cycles entirely.
<ul>
<li>Implicit description via Plucker relations</li>
<li>Inductive description (for <img src='http://l.wordpress.com/latex.php?latex=%5Cmathfrak%7Bsl%7D_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathfrak{sl}_n' title='\mathfrak{sl}_n' class='latex' /> later extended to types B and C by **FIXME**)</li>
<li>Reduction to dim-2: higher dimensional MV-polytopes are all polytopes whose 2-faces are MV-polytopes.</li>
<li>Construction from primitives: MV-polytopes are Minkowski sums of &#8220;primitives&#8221; and sums of primitives from the same &#8220;cluster&#8221; are MV-polytopes</li>
<li>In dimension 2, clusters can be described by networks of non-overlapping cords each parallel to a sides of the Weyl polytope</li>
</ul>
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		<title>A conjecture on the Uniqueness of MV-Polytopes</title>
		<link>http://trdunlap2.wordpress.com/2009/07/06/a-conjecture-on-the-uniqueness-of-mv-polytopes/</link>
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		<pubDate>Mon, 06 Jul 2009 18:36:23 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Fix a lattice L with  and a partial order . Define


(Alternatively we could fix  and define .  Similarly we might fix L^+ without reference to any inner product.)
We say that a set of &#8220;characters&#8221;  and a set of subsets  satisfy the &#8220;tensor property&#8221; if:


 where


(Here  indicates convolution and  [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=320&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Fix a lattice L with <img src='http://l.wordpress.com/latex.php?latex=%5Clangle+%2C+%5Crangle&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\langle , \rangle' title='\langle , \rangle' class='latex' /> and a partial order <img src='http://l.wordpress.com/latex.php?latex=%5Cle&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\le' title='\le' class='latex' />. Define<br />
<img src='http://l.wordpress.com/latex.php?latex=Q%5E%2B%3D%5C%7Bx%5Cin+L%7Cx%5Cge+0%5C%7D+%3D+%5Ctext%7B%60%60positive+root+cone%27%27%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Q^+=\{x\in L|x\ge 0\} = \text{``positive root cone&#039;&#039;}' title='Q^+=\{x\in L|x\ge 0\} = \text{``positive root cone&#039;&#039;}' class='latex' /><br />
<img src='http://l.wordpress.com/latex.php?latex=L%5E%2B%3D%5C%7Bx%5Cin+L%7C%5Clangle+x%2Cy%5Crangle+%5Cge+0+%5Cforall+y%5Cin+Q%5E%2B%5C%7D+%3D+%5Ctext%7B%60%60dominant+weights%27%27%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='L^+=\{x\in L|\langle x,y\rangle \ge 0 \forall y\in Q^+\} = \text{``dominant weights&#039;&#039;}' title='L^+=\{x\in L|\langle x,y\rangle \ge 0 \forall y\in Q^+\} = \text{``dominant weights&#039;&#039;}' class='latex' /><br />
(Alternatively we could fix <img src='http://l.wordpress.com/latex.php?latex=Q%5E%2B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Q^+' title='Q^+' class='latex' /> and define <img src='http://l.wordpress.com/latex.php?latex=x%5Cge+y+%5Ciff+x-y%5Cin+Q%5E%2B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x\ge y \iff x-y\in Q^+' title='x\ge y \iff x-y\in Q^+' class='latex' />.  Similarly we might fix L^+ without reference to any inner product.)</p>
<p>We say that a set of &#8220;characters&#8221; <img src='http://l.wordpress.com/latex.php?latex=%5C%7B%5Cchi_%5Clambda%3AL%5Crightarrow%5Cmathbb%7BN%7D%5C%7D_%7B%5Clambda%5Cin+L%5E%2B%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\{\chi_\lambda:L\rightarrow\mathbb{N}\}_{\lambda\in L^+}' title='\{\chi_\lambda:L\rightarrow\mathbb{N}\}_{\lambda\in L^+}' class='latex' /> and a set of subsets <img src='http://l.wordpress.com/latex.php?latex=%5C%7BM%5E%5Clambda_%5Cmu+%5Csubset+L%5C%7D_%7B%5Clambda%2C%5Cmu%5Cin+L%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\{M^\lambda_\mu \subset L\}_{\lambda,\mu\in L}' title='\{M^\lambda_\mu \subset L\}_{\lambda,\mu\in L}' class='latex' /> satisfy the &#8220;tensor property&#8221; if:</p>
<ol>
<li><img src='http://l.wordpress.com/latex.php?latex=%5Cchi_%5Clambda%28%5Cmu%29%3D%5C%23%5C%7Bm%5Cin+M%5E%5Clambda_%5Cmu+%7C+m%5Csubset+%5Ctext%7Bsupp%7D+%5Cchi_%5Clambda%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\chi_\lambda(\mu)=\#\{m\in M^\lambda_\mu | m\subset \text{supp} \chi_\lambda\}' title='\chi_\lambda(\mu)=\#\{m\in M^\lambda_\mu | m\subset \text{supp} \chi_\lambda\}' class='latex' /></li>
<li><img src='http://l.wordpress.com/latex.php?latex=%5Cchi_%7B%5Clambda_1%7D+%2A+%5Cchi_%7B%5Clambda_2%7D%3D%5Csum+c%5E%7B%5Clambda_1%2C%5Clambda_2%7D_%5Cmu+%5Cchi_%5Cmu&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\chi_{\lambda_1} * \chi_{\lambda_2}=\sum c^{\lambda_1,\lambda_2}_\mu \chi_\mu' title='\chi_{\lambda_1} * \chi_{\lambda_2}=\sum c^{\lambda_1,\lambda_2}_\mu \chi_\mu' class='latex' /> where<br />
<img src='http://l.wordpress.com/latex.php?latex=c%5E%7B%5Clambda_1%2C%5Clambda_2%7D_%5Cmu%3D+%5C%23%5C%7B+m+%5Cin++M%5E%7B%5Clambda_1%2B%5Clambda_2%7D_%5Cmu++%7C+m%5Csubset+%28%28%5Ctext%7Bsupp%7D%5Cchi_%7B%5Clambda_1%7D%29%2B%5Clambda_2%29%5Ccap%28%5Cmu%2B%5Clambda_2-%5Ctext%7Bsupp%7D%5Cchi_%7B%5Clambda_2%7D%29%29%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='c^{\lambda_1,\lambda_2}_\mu= \#\{ m \in  M^{\lambda_1+\lambda_2}_\mu  | m\subset ((\text{supp}\chi_{\lambda_1})+\lambda_2)\cap(\mu+\lambda_2-\text{supp}\chi_{\lambda_2}))\}' title='c^{\lambda_1,\lambda_2}_\mu= \#\{ m \in  M^{\lambda_1+\lambda_2}_\mu  | m\subset ((\text{supp}\chi_{\lambda_1})+\lambda_2)\cap(\mu+\lambda_2-\text{supp}\chi_{\lambda_2}))\}' class='latex' /></li>
</ol>
<p>(Here <img src='http://l.wordpress.com/latex.php?latex=%2A&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='*' title='*' class='latex' /> indicates convolution and <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BN%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{N}' title='\mathbb{N}' class='latex' /> includes zero.)</p>
<p>Suppose we also require the following about <img src='http://l.wordpress.com/latex.php?latex=%5C%7BM%5E%5Clambda_%5Cmu%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\{M^\lambda_\mu\}' title='\{M^\lambda_\mu\}' class='latex' /></p>
<ol start="0">
<li><img src='http://l.wordpress.com/latex.php?latex=M%5E%5Clambda_%5Cmu%5Cneq%5Co+%5Ciff+%5Clambda%5Cge%5Cmu&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='M^\lambda_\mu\neq\o \iff \lambda\ge\mu' title='M^\lambda_\mu\neq\o \iff \lambda\ge\mu' class='latex' /></li>
<li><img src='http://l.wordpress.com/latex.php?latex=m%5Cin+M%5E%5Clambda_%5Cmu%5CRightarrow+%5Cmu%5Cle+x%5Cle%5Clambda+%5Cforall+x%5Cin+m+%5Ctext%7B+and+%7D+%5Cmu%2C%5Clambda%5Cin+m&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='m\in M^\lambda_\mu\Rightarrow \mu\le x\le\lambda \forall x\in m \text{ and } \mu,\lambda\in m' title='m\in M^\lambda_\mu\Rightarrow \mu\le x\le\lambda \forall x\in m \text{ and } \mu,\lambda\in m' class='latex' /></li>
<li><img src='http://l.wordpress.com/latex.php?latex=m%5Cin+M%5E%5Clambda_%5Cmu%5CRightarrow+m%2Ba%5Cin+M%5E%7B%5Clambda%2Ba%7D_%7B%5Cmu%2Ba%7D+%5Cforall+a%5Cin+L+%5Ctext%7B+and+%7D+%28-m%29%5Cin+M%5E%7B-%5Cmu%7D_%7B-%5Clambda%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='m\in M^\lambda_\mu\Rightarrow m+a\in M^{\lambda+a}_{\mu+a} \forall a\in L \text{ and } (-m)\in M^{-\mu}_{-\lambda}' title='m\in M^\lambda_\mu\Rightarrow m+a\in M^{\lambda+a}_{\mu+a} \forall a\in L \text{ and } (-m)\in M^{-\mu}_{-\lambda}' class='latex' /></li>
<li>(*)<img src='http://l.wordpress.com/latex.php?latex=%5Csigma+a%5Cin+M%5E%7B%5Csigma%5Clambda%7D_%7B%5Csigma%5Cmu%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\sigma a\in M^{\sigma\lambda}_{\sigma\mu}' title='\sigma a\in M^{\sigma\lambda}_{\sigma\mu}' class='latex' /> for any isotopy, <img src='http://l.wordpress.com/latex.php?latex=%5Csigma&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\sigma' title='\sigma' class='latex' /> of <img src='http://l.wordpress.com/latex.php?latex=Q%5E%2B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Q^+' title='Q^+' class='latex' />.</li>
</ol>
<p>(I&#8217;m not sure if the last condition is worded correctly, but I&#8217;d like the collection to be invariant under permutations of, for example, minuscule weights.)</p>
<p>And, fixing a group W acting on L for which <img src='http://l.wordpress.com/latex.php?latex=L%5E%2B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='L^+' title='L^+' class='latex' /> is a fundamental domain, suppose we require that:</p>
<ol start="4">
<li><img src='http://l.wordpress.com/latex.php?latex=%5Cchi_%5Clambda%28%5Cmu%29%3D%5Cchi_%5Clambda%28w%5Cmu%29+%5Cforall+w%5Cin+W&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\chi_\lambda(\mu)=\chi_\lambda(w\mu) \forall w\in W' title='\chi_\lambda(\mu)=\chi_\lambda(w\mu) \forall w\in W' class='latex' /></li>
</ol>
<p><strong>Conjecture</strong> For <img src='http://l.wordpress.com/latex.php?latex=L%2CQ%5E%2B%2CL%5E%2B%2CW&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='L,Q^+,L^+,W' title='L,Q^+,L^+,W' class='latex' /> there is only one <img src='http://l.wordpress.com/latex.php?latex=%5C%7BM%5E%5Clambda_%5Cmu%5C%7D_%7B%5Clambda%2C%5Cmu%5Cin+L%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\{M^\lambda_\mu\}_{\lambda,\mu\in L}' title='\{M^\lambda_\mu\}_{\lambda,\mu\in L}' class='latex' /> (and corresponding <img src='http://l.wordpress.com/latex.php?latex=%5C%7B+%5Cchi_%5Clambda%5C%7D_%7B%5Clambda%5Cin+L%5E%2B%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\{ \chi_\lambda\}_{\lambda\in L^+}' title='\{ \chi_\lambda\}_{\lambda\in L^+}' class='latex' />) satisfying the tensor property and all the above requirements.</p>
<p>For <img src='http://l.wordpress.com/latex.php?latex=L%2CQ%5E%2B%2CL%5E%2B%2CW&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='L,Q^+,L^+,W' title='L,Q^+,L^+,W' class='latex' /> coming from <img src='http://l.wordpress.com/latex.php?latex=%5Cmathfrak%7Bsl_3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathfrak{sl_3}' title='\mathfrak{sl_3}' class='latex' /> or  <img src='http://l.wordpress.com/latex.php?latex=%5Cmathfrak%7Bsp_4%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathfrak{sp_4}' title='\mathfrak{sp_4}' class='latex' /> it seems to be true.</p>
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		<title>Zero-stability: Examples</title>
		<link>http://trdunlap2.wordpress.com/2009/05/04/zero-stability-examples/</link>
		<comments>http://trdunlap2.wordpress.com/2009/05/04/zero-stability-examples/#comments</comments>
		<pubDate>Mon, 04 May 2009 20:46:25 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Example zero
Suppose I consists of a single element.  Then a zero stable module is pair of maps  and  such that  is surjective,  is injective and .
The existence of zero-stable modules is only possible then if the dimension of W is at least twice the dimension of V.  In the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=316&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><h3>Example zero</h3>
<p>Suppose I consists of a single element.  Then a zero stable module is pair of maps <img src='http://l.wordpress.com/latex.php?latex=a%3AW%5Crightarrow+V&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a:W\rightarrow V' title='a:W\rightarrow V' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=b%3AV%5Crightarrow+W&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b:V\rightarrow W' title='b:V\rightarrow W' class='latex' /> such that <img src='http://l.wordpress.com/latex.php?latex=a&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a' title='a' class='latex' /> is surjective, <img src='http://l.wordpress.com/latex.php?latex=b&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b' title='b' class='latex' /> is injective and <img src='http://l.wordpress.com/latex.php?latex=ab%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='ab=0' title='ab=0' class='latex' />.</p>
<p>The existence of zero-stable modules is only possible then if the dimension of W is at least twice the dimension of V.  In the case of the smallest possible example of this (when W is 2-dimensionl) we are essentially picking two non-zero orthogonal vectors in W. </p>
<h3>Example 1</h3>
<p>Let <img src='http://l.wordpress.com/latex.php?latex=%28I%2C%5COmega%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(I,\Omega)' title='(I,\Omega)' class='latex' /> be a directed graph and V be chosen so that <img src='http://l.wordpress.com/latex.php?latex=Hom%28V_%7Bs%28h%29%7D%2CV_%7Be%28h%29%7D%29%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Hom(V_{s(h)},V_{e(h)})=0' title='Hom(V_{s(h)},V_{e(h)})=0' class='latex' /> for all h.  Then zero-stable modules are possible only when  <img src='http://l.wordpress.com/latex.php?latex=%5Cdim+W_i+%5Cge+2+%5Cdim+V_i&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\dim W_i \ge 2 \dim V_i' title='\dim W_i \ge 2 \dim V_i' class='latex' /> for all <img src='http://l.wordpress.com/latex.php?latex=i%5Cin+I&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='i\in I' title='i\in I' class='latex' />, and will correspond to a choice of zero-stable module of the type in example zero for each non-trivial <img src='http://l.wordpress.com/latex.php?latex=V_i&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='V_i' title='V_i' class='latex' />.</p>
<p>As a more specific example consider the directed graph consisting of four vertices and four edges formed into a circle.  Let <img src='http://l.wordpress.com/latex.php?latex=V_1%3DV_3%3D%5Cmathbb%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='V_1=V_3=\mathbb{C}' title='V_1=V_3=\mathbb{C}' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=V_2%3DV_0%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='V_2=V_0=0' title='V_2=V_0=0' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=W_i%3D%5Cmathbb%7BC%7D%5E2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='W_i=\mathbb{C}^2' title='W_i=\mathbb{C}^2' class='latex' />.  Then you can think of a zero-stable module as a pair of bases (each an orthogonal basis) for <img src='http://l.wordpress.com/latex.php?latex=%5Cmathbb%7BC%7D%5E2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathbb{C}^2' title='\mathbb{C}^2' class='latex' />.</p>
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		<title>0-stable Modules Part 2</title>
		<link>http://trdunlap2.wordpress.com/2009/04/25/0-stable-modules-part-2/</link>
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		<pubDate>Sat, 25 Apr 2009 18:07:32 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Fix a directed graph  and its double (I,H).  Fix I-graded vector spaces V,W.
Let  be a path in (I,H).  That is,  and  for .  The length of  is n.  Define  and .
P(H) will denote the set of all paths,  P(i,H) will denote the set of paths begining at i, and [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=310&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Fix a directed graph <img src='http://l.wordpress.com/latex.php?latex=%28I%2C%5COmega%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(I,\Omega)' title='(I,\Omega)' class='latex' /> and its double (I,H).  Fix I-graded vector spaces V,W.</p>
<p>Let <img src='http://l.wordpress.com/latex.php?latex=h_%5Cbullet%3D%28h_n%2C...+h_1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='h_\bullet=(h_n,... h_1)' title='h_\bullet=(h_n,... h_1)' class='latex' /> be a path in (I,H).  That is, <img src='http://l.wordpress.com/latex.php?latex=h_i%5Cin+H&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='h_i\in H' title='h_i\in H' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=s%28h_%7Bk%2B1%7D%29%3De%28h_k%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='s(h_{k+1})=e(h_k)' title='s(h_{k+1})=e(h_k)' class='latex' /> for <img src='http://l.wordpress.com/latex.php?latex=1%5Cle+k%5Cle+n-1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='1\le k\le n-1' title='1\le k\le n-1' class='latex' />.  The length of <img src='http://l.wordpress.com/latex.php?latex=h_%5Cbullet&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='h_\bullet' title='h_\bullet' class='latex' /> is n.  Define <img src='http://l.wordpress.com/latex.php?latex=s%28h_%5Cbullet%29%3Ds%28h_1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='s(h_\bullet)=s(h_1)' title='s(h_\bullet)=s(h_1)' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=e%28h_%5Cbullet%29%3De%28h_n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='e(h_\bullet)=e(h_n)' title='e(h_\bullet)=e(h_n)' class='latex' />.</p>
<p>P(H) will denote the set of all paths,  P(i,H) will denote the set of paths begining at i, and P(H,j) will denote the paths ending at j.  In practice we will actually these with finite sets depending on the dimension of V &#8212; I&#8217;ll address this in a moment.</p>
<p>Let (B,a,b) be a module as defined in the previous post.  <img src='http://l.wordpress.com/latex.php?latex=B_h%3AV_%7Bs%28h%29%7D%5Crightarrow+V_%7Be%28h%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B_h:V_{s(h)}\rightarrow V_{e(h)}' title='B_h:V_{s(h)}\rightarrow V_{e(h)}' class='latex' /> refers to the component of B associated to a particular edge h and <img src='http://l.wordpress.com/latex.php?latex=B_%7Bh_%5Cbullet%7D%3AV_%7Bs%28h_%5Cbullet%29%7D%5Crightarrow+V_%7Be%28h_%5Cbullet%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='B_{h_\bullet}:V_{s(h_\bullet)}\rightarrow V_{e(h_\bullet)}' title='B_{h_\bullet}:V_{s(h_\bullet)}\rightarrow V_{e(h_\bullet)}' class='latex' /> refers a composition of such maps.</p>
<p>Then we may alternatively define zero-stable as follows: (B,a,b) is zero-stable if for all <img src='http://l.wordpress.com/latex.php?latex=i%5Cin+I&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='i\in I' title='i\in I' class='latex' /> and every <img src='http://l.wordpress.com/latex.php?latex=y+%5Cin+V_i&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y \in V_i' title='y \in V_i' class='latex' /></p>
<ol>
<li>there exists a path <img src='http://l.wordpress.com/latex.php?latex=h_%5Cbullet%5Cin+P%28i%2CH%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='h_\bullet\in P(i,H)' title='h_\bullet\in P(i,H)' class='latex' /> such that <img src='http://l.wordpress.com/latex.php?latex=b_%7Be%28h_%5Cbullet%29%7DB_%7Bh_%5Cbullet%7D%28y%29%5Cneq+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_{e(h_\bullet)}B_{h_\bullet}(y)\neq 0' title='b_{e(h_\bullet)}B_{h_\bullet}(y)\neq 0' class='latex' /> and</li>
<li>there exists a vector <img src='http://l.wordpress.com/latex.php?latex=x%5Cin%5Cbigoplus_%7Bh_%5Cbullet%5Cin+P%28H%2Ci%29%7D+W_%7Bs%28h_%5Cbullet%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x\in\bigoplus_{h_\bullet\in P(H,i)} W_{s(h_\bullet)}' title='x\in\bigoplus_{h_\bullet\in P(H,i)} W_{s(h_\bullet)}' class='latex' /> such that <img src='http://l.wordpress.com/latex.php?latex=%5Csum+B_%7Bh_%5Cbullet%7Da_%7Bs%28h_%5Cbullet%29%7D%28x_%7Bs%28h_%5Cbullet%29%7D%29%3Dy&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\sum B_{h_\bullet}a_{s(h_\bullet)}(x_{s(h_\bullet)})=y' title='\sum B_{h_\bullet}a_{s(h_\bullet)}(x_{s(h_\bullet)})=y' class='latex' />.</li>
</ol>
<p>The proof that this is equivelant to the previous definition is straightforward and also demonstrates that we need only consider paths that visit each vertex <img src='http://l.wordpress.com/latex.php?latex=i&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='i' title='i' class='latex' /> no more than <img src='http://l.wordpress.com/latex.php?latex=%5Cdim%28V_i%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\dim(V_i)' title='\dim(V_i)' class='latex' /> times.</p>
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		<title>0-stable Modules</title>
		<link>http://trdunlap2.wordpress.com/2009/04/24/0-stable-modules/</link>
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		<pubDate>Fri, 24 Apr 2009 22:24:35 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[For Nakajima&#8217;s analogue of MV-cycles we need to understand what it takes for a &#8220;module&#8221; to be 0-stable.  Let me review first what that means.
Fix a finite set I={1 .. r} and a directed graph (I,).  Let . For two I-graded vector spaces V and W we define


.
(where s and e denote the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=304&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>For Nakajima&#8217;s analogue of MV-cycles we need to understand what it takes for a &#8220;module&#8221; to be 0-stable.  Let me review first what that means.</p>
<p>Fix a finite set I={1 .. r} and a directed graph (I,<img src='http://l.wordpress.com/latex.php?latex=%5COmega&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\Omega' title='\Omega' class='latex' />).  Let <img src='http://l.wordpress.com/latex.php?latex=H%3D%5COmega%5Csqcup%5Cbar%5COmega&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='H=\Omega\sqcup\bar\Omega' title='H=\Omega\sqcup\bar\Omega' class='latex' />. For two I-graded vector spaces V and W we define<br />
<img src='http://l.wordpress.com/latex.php?latex=E%28V%2CW%29%3D%5Cbigoplus_%7Bh%5Cin+H%7D+Hom%28V_%7Bs%28h%29%7D%2CW_%7Be%28h%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='E(V,W)=\bigoplus_{h\in H} Hom(V_{s(h)},W_{e(h)}' title='E(V,W)=\bigoplus_{h\in H} Hom(V_{s(h)},W_{e(h)}' class='latex' /><br />
<img src='http://l.wordpress.com/latex.php?latex=L%28V%2CW%29%3D%5Cbigoplus_%7Bi%5Cin+I%7D+Hom%28V_i%2CW_i%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='L(V,W)=\bigoplus_{i\in I} Hom(V_i,W_i)' title='L(V,W)=\bigoplus_{i\in I} Hom(V_i,W_i)' class='latex' /><br />
<img src='http://l.wordpress.com/latex.php?latex=M%28V%2CW%29%3DE%28V%2CV%29%5Coplus+L%28W%2CV%29+%5Coplus+L%28V%2CW%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='M(V,W)=E(V,V)\oplus L(W,V) \oplus L(V,W)' title='M(V,W)=E(V,V)\oplus L(W,V) \oplus L(V,W)' class='latex' />.<br />
(where s and e denote the start and end vertices of an edge.)<br />
We have a function<br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cepsilon%3AE%28V%2CV%29%5Crightarrow+E%28V%2CV%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\epsilon:E(V,V)\rightarrow E(V,V)' title='\epsilon:E(V,V)\rightarrow E(V,V)' class='latex' /><br />
which multiplies by -1 components corresponding to <img src='http://l.wordpress.com/latex.php?latex=h%5Cin%5Cbar%5COmega&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='h\in\bar\Omega' title='h\in\bar\Omega' class='latex' /> and fixes components corresponding to <img src='http://l.wordpress.com/latex.php?latex=h%5Cin%5COmega&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='h\in\Omega' title='h\in\Omega' class='latex' />.  We have a composition<br />
<img src='http://l.wordpress.com/latex.php?latex=L%28V%2CW%29%5Ctimes+L%28W%2CX%29+%5Crightarrow+L%28V%2CX%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='L(V,W)\times L(W,X) \rightarrow L(V,X)' title='L(V,W)\times L(W,X) \rightarrow L(V,X)' class='latex' /><br />
which is straightforward. We have a composition<br />
<img src='http://l.wordpress.com/latex.php?latex=E%28V%2CW%29%5Ctimes+E%28W%2CX%29+%5Crightarrow+L%28V%2CX%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='E(V,W)\times E(W,X) \rightarrow L(V,X)' title='E(V,W)\times E(W,X) \rightarrow L(V,X)' class='latex' /><br />
where <img src='http://l.wordpress.com/latex.php?latex=%28CB%29_i%3D%5Csum_%7Be%28h%29%3Di%7D+C_hB_%7B%5Cbar+h%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(CB)_i=\sum_{e(h)=i} C_hB_{\bar h}' title='(CB)_i=\sum_{e(h)=i} C_hB_{\bar h}' class='latex' />. And we have a &#8220;moment map vanishing at the origin&#8221;<br />
<img src='http://l.wordpress.com/latex.php?latex=%5Cmu%3AM%28V%2CW%29%5Crightarrow+L%28V%2CV%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu:M(V,W)\rightarrow L(V,V)' title='\mu:M(V,W)\rightarrow L(V,V)' class='latex' /><br />
where <img src='http://l.wordpress.com/latex.php?latex=%5Cmu%28B%2Ca%2Cb%29%3D%28%5Cepsilon+B%29B%2Bab&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mu(B,a,b)=(\epsilon B)B+ab' title='\mu(B,a,b)=(\epsilon B)B+ab' class='latex' />.</p>
<p>From now on we fix V and W.</p>
<p>A point <img src='http://l.wordpress.com/latex.php?latex=%28B%2Ca%2Cb%29%5Cin%5Cmu%5E%7B-1%7D%280%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(B,a,b)\in\mu^{-1}(0)' title='(B,a,b)\in\mu^{-1}(0)' class='latex' /> is called a &#8220;module&#8221;.</p>
<p>A &#8220;sub-module&#8221; of (B,a,b) is a B-invariant I-graded vector space <img src='http://l.wordpress.com/latex.php?latex=V%27%5Csubset+V&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='V&#039;\subset V' title='V&#039;\subset V' class='latex' /> which either contains Im(a) or is contained in Ker(b).</p>
<p>A module (B,a,b) is said to be &#8220;0-stable&#8221; if the only sub-modules are 0 and V.</p>
<p>**EDIT: I should say (B,a,b) is zero-stable if the only sub-module containing Im(a) is V and the only submodule contained in Ker(b) is 0.</p>
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		<title>Primative Polytopes and Tropical Relations</title>
		<link>http://trdunlap2.wordpress.com/2009/02/14/primative-polytopes-and-tropical-relations/</link>
		<comments>http://trdunlap2.wordpress.com/2009/02/14/primative-polytopes-and-tropical-relations/#comments</comments>
		<pubDate>Sat, 14 Feb 2009 18:07:53 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://trdunlap2.wordpress.com/?p=296</guid>
		<description><![CDATA[My attention was drawn this week to another part of Kamnitzer&#8217;s paper on MV-polytopes were he discusses clusters of primitive polytopes (observed by Anderson).  Primitive polytopes are a finitie set (for the finite dimensional groups anyway) of polytopes that generate all MV-polytopes under Minkowski sum.  MV-polytopes aren&#8217;t closed under Minkowski sum, but the primitive polytopes [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=296&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>My attention was drawn this week to another part of Kamnitzer&#8217;s paper on MV-polytopes were he discusses clusters of primitive polytopes (observed by Anderson).  Primitive polytopes are a finitie set (for the finite dimensional groups anyway) of polytopes that generate all MV-polytopes under Minkowski sum.  MV-polytopes aren&#8217;t closed under Minkowski sum, but the primitive polytopes are grouped into clusters such that taking Minkowski sum within a cluster guarantees an MV-polytope.  Prehaps I should emphasize, every MV-polytope can be written as the Minkowski sum of a set of primitive polytopes found in the same cluster.</p>
<p>The clusters correspond to tropical choices.  When we have a tropical formula <img src='http://l.wordpress.com/latex.php?latex=A%3Dmin%5C%7BB%2CC%2CD%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A=min\{B,C,D\}' title='A=min\{B,C,D\}' class='latex' /> this can be rephrased as:</p>
<p><img src='http://l.wordpress.com/latex.php?latex=A%3DB%2CA%5Cle+C%2CA%5Cle+D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A=B,A\le C,A\le D' title='A=B,A\le C,A\le D' class='latex' /> OR<br />
<img src='http://l.wordpress.com/latex.php?latex=A%3DC%2CA%5Cle+D%2CA%5Cle+B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A=C,A\le D,A\le B' title='A=C,A\le D,A\le B' class='latex' /> OR<br />
<img src='http://l.wordpress.com/latex.php?latex=A%3DD%2CA%5Cle+B%2CA%5Cle+C&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A=D,A\le B,A\le C' title='A=D,A\le B,A\le C' class='latex' /></p>
<p>So the solution set to a tropcal formula is a union of cones.  Each of these cones (generally overlapping) correspond to a tropical choice.   If an MV polytope satisfies the tropical Plucker relations with a particular tropical choice &#8212; then it can be generated via Minkowski sum by polytopes in the cluster corresponding to that tropical choice.</p>
<p>I&#8217;m very interested in this because for $latex  L\mathfrak{sl}_2$ I don&#8217;t have a satisfactory sense of tropical Plucker relations, but I do have a notion of &#8220;MV-polytopes&#8221; (not yet realized as moment map images of cycles, but functioning combinatorially in the same way) and of course Minkowski sum.   So if I can observe primitives and  clusters, I may gain some insight into what sort of tropical relations to expect.</p>
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		<title>Tensoring Polytopes, Minkowski Sum Method (pictures)</title>
		<link>http://trdunlap2.wordpress.com/2009/02/06/tensoring-polytopes-minkowski-sum-method-pictures/</link>
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		<pubDate>Fri, 06 Feb 2009 06:33:05 +0000</pubDate>
		<dc:creator>trdunlap2</dc:creator>
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		<description><![CDATA[Here&#8217;s a case in  we should all be familiar with.
If we tensor the standard representation with the standard dual we get a nine-dimensional representation:

Say the red polytopes come from Standard and the blue come from Standard dual (black is the overlap).  In the Minkowski sum method the MV-polytopes are &#8220;added&#8221; head-to-tail style.
In this method [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=trdunlap2.wordpress.com&blog=2267099&post=290&subd=trdunlap2&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Here&#8217;s a case in <img src='http://l.wordpress.com/latex.php?latex=%5Cmathfrak%7Bsl%7D_3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\mathfrak{sl}_3' title='\mathfrak{sl}_3' class='latex' /> we should all be familiar with.</p>
<p>If we tensor the standard representation with the standard dual we get a nine-dimensional representation:</p>
<p><img class="alignnone size-full wp-image-291" title="sttimesstd" src="http://trdunlap2.files.wordpress.com/2009/02/sttimesstd.png?w=442&#038;h=423" alt="sttimesstd" width="442" height="423" /></p>
<p>Say the red polytopes come from Standard and the blue come from Standard dual (black is the overlap).  In the Minkowski sum method the MV-polytopes are &#8220;added&#8221; head-to-tail style.</p>
<p>In this method the action on a basis vector is given by <img src='http://l.wordpress.com/latex.php?latex=g%28x%5Cotimes+y%29%3D%28gx%29%5Cotimes+y+%2B+x%5Cotimes+%28gy%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g(x\otimes y)=(gx)\otimes y + x\otimes (gy)' title='g(x\otimes y)=(gx)\otimes y + x\otimes (gy)' class='latex' /> so the adjoint representation inside (recall <img src='http://l.wordpress.com/latex.php?latex=St%5Cotimes+St%5E%2A%3DAd%5Coplus+Tr&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='St\otimes St^*=Ad\oplus Tr' title='St\otimes St^*=Ad\oplus Tr' class='latex' />) looks like this:</p>
<p><img class="alignnone size-full wp-image-293" title="adinsttimesstd1" src="http://trdunlap2.files.wordpress.com/2009/02/adinsttimesstd1.png?w=449&#038;h=380" alt="adinsttimesstd1" width="449" height="380" /></p>
<p>And the trivial representation inside looks like:</p>
<p><img class="alignnone size-full wp-image-294" title="trinsttimesstd" src="http://trdunlap2.files.wordpress.com/2009/02/trinsttimesstd.png?w=298&#038;h=99" alt="trinsttimesstd" width="298" height="99" /></p>
<p>The signs will be explained in the next post when I go into what I call &#8220;Anderson method&#8221;.  For now, notice that this makes <img src='http://l.wordpress.com/latex.php?latex=Ad%5Coplus+Tr&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Ad\oplus Tr' title='Ad\oplus Tr' class='latex' /> and orthogonal sum with respect to the tensor basis.</p>
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